c++ cast double to int is a trick to convert a double to an int. It’s a neat trick, but it doesn’t actually work.
Yes it does. An int is two bits, so a double is two bytes, which is enough to hold values of about the same size. The trick is c cast double to int, which takes two ints and casts them to double. So in essence, you can cast any double to an int, and then you can do the same thing with any int.
The problem is that in this case, casting a double to an int is not quite the same as casting a double to an int. Casting a double to an int actually converts it to an int, but the conversion to an int is done using the type of the object, not the type of the double.
This is an issue that affects the very existence of double. C developers have been working on a fix for it for a long time, but so far it is not ready for general use, and it’s still considered experimental. For a double, the casting will actually convert it to an int, but this conversion is just an optimization (or more accurately a reinterpret_cast). The compiler may actually use the “double” type when converting to int, but this is not guaranteed.
It’s just a problem with double, not a problem with its type. The cast will not convert it to int, but the compiler will in fact perform this conversion.
The cast doesn’t have to work. It just needs to convert to int.
In fact, as a double, the cast will convert to an int. However, the compiler may not do the conversion. Therefore, you will have to explicitly convert your double to int.
With that out of the way, I hope you’ve heard of c++ cast because I’d love to explain what this line of code does. c++ cast converts one type that is double to another type that is int.
As far as I can tell, this is a line of code that converts an int to a double, and then you use the convert or cast instructions to convert the double back to an int.
For example, if I wanted to convert 8.1 to a double, I would do 8.1 * 1.0 to get the double. If I wanted to convert 12.1 to a double, I would do 12.1 * 2.0 to get the double.